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4x^2-27x-900=0
a = 4; b = -27; c = -900;
Δ = b2-4ac
Δ = -272-4·4·(-900)
Δ = 15129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15129}=123$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-123}{2*4}=\frac{-96}{8} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+123}{2*4}=\frac{150}{8} =18+3/4 $
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